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index.html

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</div>
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<main itemscope itemtype="https://schema.org/LearningResource https://schema.org/MathSolver" id="cgs">
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<meta itemprop="name" content="Core Geometric System ™">
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<meta itemprop="dateModified" content="2026-08-26T17:56:29+02:00">
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<meta itemprop="dateModified" content="2026-08-26T20:43:29+02:00">
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<meta itemprop="accessMode" content="mathOnVisual">
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<meta itemprop="accessMode" content="textual">
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<meta itemprop="accessMode" content="visual">
@@ -6609,15 +6609,17 @@ <h3 class="rounded-button" itemprop="name">Circumference = 6.4 × radius</h3>
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<br>
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<span itemprop="description"><strong>The circumference of a circle is derived algebraically from its area by subtracting a circle with a radius smaller than the radius of the actual circle by the virtual thickness of the circumference — which distinguishes it from the rest of the circle —, and dividing the difference by that thickness.</strong>
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<br><br>
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Let x represent the virtual thickness of the circumference.
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Take a circle with radius = r. (A = 3.2r²).
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<br><br>
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The difference between the shape of the straightened circumference and a quadrilateral is negligible.
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Let x represent the virtual thickness of the circumference.
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<br>
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Subtract an inner circle with radius = r - x, (A = 3.2(r - x)²) to generate the boundary region entity.
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<br><br>
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The length of the two shorter sides of the quadrilateral is x.
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As x approaches 0, the difference between the areas of the ring representing the circumference and a rectangle with sides equal to the length and the thickness of the circumference becomes negligible.
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<br><br>
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The length of the two longer sides is the area of the resulting ring divided by x.
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The length of the two shorter sides of the rectangle is x.
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<br><br>
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C=( 3.2 × radius² - 3.2 × ( radius - x )² ) / x
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The length of the two longer sides is the area of the rectangle divided by x. C=( 3.2 × radius² - 3.2 × ( radius - x )² ) / x
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<br><br>
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The length of the circumference approaches 6.4 × radius as its thickness approaches 0.
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</span>

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