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Record the owner-indexed y0 defect and its monomial charge - #6951
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On the published two-edge feed, every D-exponent-0 owner index that keeps
D1 Q^{-1} and clears y0 pays the same two monomials. The constant-index
fresh image leaves the four final banks stored and leaves the x1 block unpaid.
No new kappa.
Co-authored-by: unpaidmoon <unpaidmoon@users.noreply.github.com>
This was referenced Nov 10, 2026
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Change and mathematical scope
Scoped identity and field ledger. No new κ. The selected conditional value stays
781451/250000000from the selected record (PR #6030). This does not change the selected frontier.On the published two-edge feed, every owner-indexed D-exponent-0 left map of the four final banks that keeps
x0 = D1 Q^{-1}and clears y0 satisfiesThe constant index writes that defect into a fresh image. The four stored endpoint banks are not overwritten. The image's x1 block remains the published three-term coefficient and is unpaid.
This is an algebra identity on the replayed banks, not a bounded search and not a claim that every physical quotient is as expensive. The field ledger is one factored circuit under inherited units: 2016 scalar ADDs, 672 monomial passes, 32 mode CLEARs, 224 COPYs, and 336 extra fields. It is not a minimum and not a tape proof.
Task and overlap
Base:
7c49fe32c55de02c2c873655c804b16e4c3fef0a. Cardjoint-query-controller, scope refined. The card's demand is not changed. This is the owner-indexed remainder of handoff discussion comment 19138525 afterresearch/coded-active-feedbackrestored the missing coefficient.Nearest work, and why this is distinct:
research/coded-active-feedback(upstream) restoresAonly together with the y0 coupling and stops at an 8,281-policy search. It does not give this owner index or this charge.research/active-feedback-coupling-lock, proves the declared alternating family cannot separate the witness monomials, and notes one odd-Q correction without an owner-index identity or a monomial charge. That census is not rerun. The new statement is the defect identity for every D-exponent-0 owner index, plus the charge for the constant-index image.Local overlap at the base commit searched the complete note inventory and found no note containing both "owner-indexed" and "y0 coupling". The remote overlap cache was absent. A live open-PR search for
y0returned no CrocSwap pull requests. That is not a novelty certificate.Validation
Python 3.12, standard library only. Normal and optimized registered commands both pass:
Checks are explicit
needfailures. They cover the pinned replay, the finite products, the defect identity including a relocation ofQ^{-1}intom0, the fresh image, dropped-monomial failures, and the ledger arithmetic. No native build, network fetch, or full multiplier replay is used.QandQ^{-1}are charged as one monomial pass each, the predecessor'sQ^2unit; a three-factor expansion ofQ^{-1}is not settled.Credit
Cinna Davis,
research/coded-active-feedback, using Dugongue's PR4948 chronology, Dillon's PR4933 code, and the passive ceiling packaged by Chris R / Clear1nsight. The uncharged one-point correction is fork PR 152. The gauge engine is the inheritedresearch/coded-native-caller/gauge.py.Prepared by unpaidmoon with substantial Cursor Grok assistance. Apache-2.0.
Open next questions
Can a fresh image clear the three-term x1 block while keeping x0, keeping y0 zero, and leaving the four final banks stored unchanged? Start with the same four-bank equation on the x1 column. This package leaves that coefficient in place.
Does one inherited monomial pass implement
QandQ^{-1}? Bind the source primitive for a single power ofQbefore treating 672 monomial passes as a tape cost.Workflow feedback (optional)
The revision-8 priority note still prints κ = 0.00310045 from PR #5599, while
certificates/selected-result.jsonhas781451/250000000. The selected record is the right orientation pin. One link to the feedback discussion is enough: #1200