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Record that a rank-4 length-30 sojourn needs at least 17 layer-0 points (no κ) - #7093
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The normalized two-point fiber census is empty, so a universal word in the 8-to-14 layer-1 window needs at least 17 layer-0 projections. Selected kappa is unchanged. Co-authored-by: unpaidmoon <unpaidmoon@users.noreply.github.com>
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Change and mathematical scope
Scoped proof, with an exhaustive finite census. No new κ and no selected-frontier change. Selected κ stays
781451/250000000.In the restored binary singleton model,
28 <= f(8) <= 32is unchanged. For a closed length-30 word, a multiplicity-2 sojourn of rank 4 cannot have exactly 16 distinct layer-0 projections. Inside the stated window of 8 to 14 layer-1 projections, every such sojourn therefore has at least 17 layer-0 projections and at most 13 layer-1 projections. The 14-point layer-1 boundary is empty.The sixteen-point nonexistence is a proof. Its finite step is an exhaustive census of the
120^7normalized two-point fiber tuples, after fixing the identity fiber as{0, 1}. The prune is proved sound inPROOF.md. The census finds no cover: 57,685,490 nodes, 0 solutions. This is not a heuristic search, and it is not a proof that no universal length-30 word exists. It does not changef(8).The same pair and fiber inequalities also admit
|Q1| = 6with|Q0| = 24. That case sits outside the 8-to-14 search named in the source question and is not censused. Ranks 5 and 6, and length 28, are not examined. The length-32 Gray concatenation remains a universal upper example. The recorded coverage-255 word, missing only mask 131, has a rank-4 sojourn with 21 layer-0 projections and 9 layer-1 projections, so it still meets the new floor.Task and overlap
Base commit:
17469fff78c22941280f04d39dc5a1faee09c840.Session r150, the length-30 rank-at-least-4 sojourn search. The assigned item is open question 1 of upstream pull request 7015. The first step there is to fix one rank-4 multiplicity-2 source whose layer-1 projection has between 8 and 14 points and search the complementary arc with at least 16 layer-0 projections. This package censuses the size-16 boundary of that arc. It does not rerun the rank-3 obstruction, the rank-at-most-2 obstruction, the bent census, the 4+4 prefix-set argument, or the length-28 sharpness question.
Card
connector-alphabet-change, priority revision 8. Scope status: changed. The card asks for one new connector operation. This package stays in the published singleton alphabet and settles only the 16-point rank-4 layer.Nearest work:
f(7) = 24, which is not used here.28 <= f(8) <= 32.Upstream main was re-fetched at session start and was still
17469fff78c22941280f04d39dc5a1faee09c840. An open-PR search for a length-30 rank-4 layer census found #7015 and no package that decides this boundary.Validation
CPython 3.12 and gcc, standard library, from the repository root:
Observed:
PASS_LENGTH30_RANK4_LAYER16 solutions=0 nodes=57685490 branch1_nodes=515051 layer0_floor=17 layer1_ceiling=13 witness_coverage=255PASS_REGISTERED_RESEARCH_PACKAGE research/length30-rank4-layer-floor outcome=partialPASS_RESEARCH_COMMIT_BYTESat94b36d4649b5d29829959409acbc1906ef0b4379The C census and a nested Python recount of second-fiber index 1 agree on 515,051 nodes and zero solutions for that branch. A fixed eight-fiber fixture partitions the odd quotient directions and misses the even ones. The coverage-255 witness, a swapped-pair failure control, the normalized rank-4 layers of that witness, and the Gray concatenation of length 32 are checked.
f(7) = 24was not replayed. The seventeen-point fiber census, ranks 5 and 6, and length 28 were not searched. No Lean, Docker, or selected cold replay was run. The source-history preflight was not run: the checkout is shallow, and that preflight requires full Git history.Credit
Ross Richardson, #943, for the singleton model and prefix criterion. Douglas Colkitt, #1185, for the length-32 construction. conorholds, #3058, for
f(7) = 24and the eight-source question; that theorem is not used. Nick Petalas, #5234 and discussion comment 19377982, for the deletion floor and the length-30 handoff. Nicholas Stone, #5430, for the fixed-projection lift obstruction that this split does not reuse. Upstream pull request 6943 for the rank-at-most-2 obstruction, the bent lower bound, the 4+4 argument, and the coverage-255 witness. Open pull request 7015 for the rank-3 blockage and for the rank-4 window whose sixteen-point boundary is settled here.Prepared by unpaidmoon with substantial Cursor Grok assistance. New work is Apache-2.0. Independent human and proof-kernel review are unclaimed.
Open next questions
f(8)from 32 to 30. The coverage-255 witness still meets the tightened floor and misses only mask 131. First step: census one rank-4 layer of size 17, whose fiber shape on the 8-to-13 side is one triple and seven pairs, or search one complementary arc in that range. The size-6 layer forces exactly 24 layer-0 projections and was outside the 8-to-14 search. Blocker: at size 17 each direction has 18 sums available against 16 targets, so the exact packing used here stops. Length 28 is a different question.Workflow feedback
The quotient-fiber packing makes the size-16 boundary a single finite census, and an incremental C search agrees with a nested Python recount on the locked branch. No further session report.