Repository navigation
Prove four once-each rank-one frames miss the four-call endpoint. - #6952
Merged
Mister-Meeseeks merged 1 commit intoNov 10, 2026
Merged
Mister-Meeseeks merged 1 commit into
Mister-Meeseeks merged 1 commit into
Conversation
The shortest equation using each new label once is R+S+T+U=4I. Target support fails for every rational rank-one solution, and one explicit solution has a full parity image. No kappa change. Co-authored-by: unpaidmoon <unpaidmoon@users.noreply.github.com>
This was referenced Nov 10, 2026
Prove five once-each rank-one frames miss the five-call endpoint.
unpaidmoon/integer-mult-bounds#199
Draft
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
Add this suggestion to a batch that can be applied as a single commit.This suggestion is invalid because no changes were made to the code.Suggestions cannot be applied while the pull request is closed.Suggestions cannot be applied while viewing a subset of changes.Only one suggestion per line can be applied in a batch.Add this suggestion to a batch that can be applied as a single commit.Applying suggestions on deleted lines is not supported.You must change the existing code in this line in order to create a valid suggestion.Outdated suggestions cannot be applied.This suggestion has been applied or marked resolved.Suggestions cannot be applied from pending reviews.Suggestions cannot be applied on multi-line comments.Suggestions cannot be applied while the pull request is queued to merge.Suggestion cannot be applied right now. Please check back later.
Change and mathematical scope
Scoped support proof, plus one explicit parity-image witness. No new κ and no word.
In the PR2085/2112 model, the shortest determinant equation that uses four new labels once each is
R+S+T+U = 4I: four paid calls and no call onA,B,P, orQ. Every nonzero symmetric rational rank-one solution fails target support, so the equation admits no word. The selected record stays κ =781451/250000000.The obstruction is elementary. Each target has trace 2 and determinant
1/2, so only a pair of frames can sum to a target. All 15 ways of choosing four pairs among four calls have degree sequence(2,2,2,2)or(3,2,2,1). The first forces8I = 4I. The second forces one frame to equal-H/2, whose determinant is1/8. This is a proof for this one equation. It is not a census of directions, not a statement about lengths 5, 6, or 7, and not a statement about five or more added frames.Separately, one rational solution evades the three-frame vanishing test. Directions
(0,1),(1,-1),(1,1), and(1,2)at scales-3,5/2,1/2, and1sum to4I, and the integral span has parity image all ofF2^2. No AB or PQ form kills every added frame. That witness is still excluded by a direct count: theP-coefficient modulo 2 detects two calls and four targets. It is one solution, not a census, and Theorem 2 already says it is not a word.The determinant identity and the subset-sum necessity are inherited from
research/bit-two-signed-frame-floor(PR #6190) and are not reproved.Task and overlap
Base commit:
7c49fe32c55de02c2c873655c804b16e4c3fef0a(upstream CrocSwap main). The fork PR base iscursor/upstream-7c49fe32-pin-7237, which points at that commit. Priority revision 8. The live selected record is κ =781451/250000000from PR #6030.docs/research/current-priorities.mdstill quotes the older PR #5599 decimal; this package uses the selected record and does not change it.Task card:
bit-new-register-model,scope_status: changed. The card asks for a larger or nonabelian native alphabet. This package stays in the abelian symmetric 2-by-2 model and answers the four-frame question left open by discussion comment 19377832 and by the all-old-once finding in comment 19493126. It does not redo that three-frame proof and it does not take another three-frame census profile.Overlap rechecked on 2026-11-10: PR #6190 is merged and stops at two added frames. No open upstream PR matches this four-frame equation. Discussion #1166's newest top-level comments through 19481299, and reply 19493126, leave four or more added frames open. No
cursor/*four-signed*branch existed on the fork before this one.Validation
Python 3.12. From the repository root:
Observed:
PASS_PACKAGE_METADATA_AND_PINS,PASS_REGISTERED_RESEARCH_PACKAGEwithoutcome=completed, andPASS_RESEARCH_COMMIT_BYTESat7f2d4b3e4eca3a79a3ee1a18963732678b505ed4. The direct check ispython3 -I -W error -B research/four-signed-once-parity/verify.py, also run with-O. Both printedPASS four-signed-once-parity checks.verify.pychecks the target determinant identities, exhausts all 15 four-edge graphs, and checks the declared witness: full parity image, two detected calls against four targets, and no target among its subset sums. Failure controls reject a tampered sum, rejectIas a rank-one summand, and reject the zero matrix. The graph list is the whole pair case split. The witness is not a census of solutions.Not run:
--check-source-history, because this checkout is shallow; Lean; Docker; the selected-result cold replay; and the predecessor replay of PR #6190. Lengths 5, 6, and 7 were not searched.Credit
The register model is Cinna Davis's PR2085/2112 formal model. The determinant and the subset-sum necessity are the PR2910 package as recorded in apoursh's two-signed-frame floor, PR #6190. That floor stopped at two added frames. The three-frame all-old-once character is fork PR #155 / comment 19493126 and is not redone here. The concrete handoff is discussion comment 19377832.
Prepared by unpaidmoon with substantial Cursor Grok assistance. No independent human or formal-kernel review. New work is Apache-2.0.
Open next questions
Can four added signed rank-one frames plus one, two, or three old calls meet support at length 5, 6, or 7? Theorem 2 uses exactly four calls. A useful first step is one old projector
Eand the equationR+S+T+U = 4I-E, then the same pair test on one rational solution. No such solution is supplied here.Can five or more added signed rank-one frames lower the eight-call minimum? The four-call support proof and the three-frame character both stop at the number of frames they assume. A useful first step is five primitive directions and the shortest determinant equation that uses each new label once.
A full parity image does not by itself survive every character. The witness above is still excluded by a character that detects only two of the four frames.
Workflow feedback (optional)
The declared parity-image test and the support obstruction answer different questions. Linking this once in discussion #1200 is enough.